Adventures in SuperComputing - Summer Teacher InstituteExample Site |
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Mathematical ModelLet x(t) be the number of 'roos at time t. Then in an time interval dt, x(t) increases by 1/2*x(t). In addition, x(t) increases negatively (decreases) in dt by the amount 1/3*x(t). So, the net population increase of x(t) in the time interval dt is x(t + dt) = x(t) + 1/2*x(t) - 1/3*x(t)which reduces to the following: x(t + dt) = 1/6*x(t) |
For more information, please contact Bill Robertson, Ph.D. (robertson@lanl.gov) |